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-1x^2+0.5x+0.1=0
a = -1; b = 0.5; c = +0.1;
Δ = b2-4ac
Δ = 0.52-4·(-1)·0.1
Δ = 0.65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{0.65}}{2*-1}=\frac{-0.5-\sqrt{0.65}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{0.65}}{2*-1}=\frac{-0.5+\sqrt{0.65}}{-2} $
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